Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:56Z
2ψ² + 5ψ + 4 = 0
∫₀^∞ e^(-t²) dt = √π / 2
75K
det| 5 3 ; 7 6 | = 9
479K
N₂ + 3H₂ ⇌ 2NH₃
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
det| 5 3 ; 2 6 | = 24
191K
∇²z = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
1K
det| 7 4 ; 4 8 | = 40
153K
N₂ + 3H₂ ⇌ 2NH₃
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
8t² + 2t + 3 = 0