Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:27Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
det| 9 4 ; 1 10 | = 86
129K
F = ma
∑_{k=1}^{n} k = n(n+1)/2
191K
det| 4 4 ; 5 5 | = 0
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 10 4 ; 1 11 | = 106
1K
det| 8 9 ; 4 9 | = 36
188K