Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:02Z
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
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8β² + 2β + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 10 7 ; 3 11 | = 89
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det| 12 1 ; 1 13 | = 155
det| 5 9 ; 0 6 | = 30
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