Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:34Z
∑_{k=1}^{n} k = n(n+1)/2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
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3β² + 6β + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
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F = ma
det| 10 9 ; 0 11 | = 110
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∑_{k=1}^{n} k = n(n+1)/2
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det| 7 6 ; 1 8 | = 50
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det| 7 4 ; 4 8 | = 40
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