Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 05:00Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-φ²) dφ = √π / 2
326K
det| 7 9 ; 1 8 | = 47
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11y² + 4y + 3 = 0
d/dy [y^6] = 6y^5
det| 7 4 ; 4 8 | = 40
366K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
201K
8ω² + 6ω + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
319K
\frac{4}{2} \sum_{i=1}^{n} i^{2}