Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:12Z
∑_{k=1}^{n} k = n(n+1)/2
det| 4 6 ; 4 5 | = -4
75K
3β² + 6β + 2 = 0
F = ma
CH₄ + 2O₂ → CO₂ + 2H₂O
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
1K
∑_{k=1}^{n} k = n(n+1)/2
153K
1x² + 5x + 7 = 0