Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:27Z
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
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\frac{8}{9} \sum_{i=1}^{n} i^{2}
F = ma
\binom{n}{k} = \frac{n!}{k!(n-k)!}
390K
10n² + 4n + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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d/dy [y^11] = 11y^10
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