Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 22:05Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
12β² + 9β + 3 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∂z/∂n = 8z
e^{i\pi} + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-φ²) dφ = √π / 2
473K
∫₀^∞ e^(-x²) dx = √π / 2
338K
2H₂ + O₂ → 2H₂O
det| 9 4 ; 1 10 | = 86
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