Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:49Z
∇²α = 0
6φ² + 8φ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
155K
∂φ/∂φ = 1φ
∑_{k=1}^{n} k = n(n+1)/2
366K
det| 7 4 ; 4 8 | = 40
201K
det| 4 8 ; 1 5 | = 12
det| 11 9 ; 5 12 | = 87
176K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
263K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
233K
∇²r = 0