Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:26Z
∇ × E = −∂B/∂t
det| 5 3 ; 2 6 | = 24
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∑_{k=1}^{n} k = n(n+1)/2
479K
\frac{8}{9} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-t²) dt = √π / 2
276K
F = ma
10n² + 4n + 5 = 0
det| 9 4 ; 1 10 | = 86
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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