Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:26Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
det| 4 8 ; 3 5 | = -4
276K
det| 11 9 ; 0 12 | = 132
129K
F = ma
∑_{k=1}^{n} k = n(n+1)/2
191K
CH₄ + 2O₂ → CO₂ + 2H₂O
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}