Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 23:01Z
d/dα [α^11] = 11α^10
∑_{k=1}^{n} k = n(n+1)/2
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\frac{3}{5} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
392K
λ = h/p
det| 5 2 ; 3 6 | = 24
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det| 10 4 ; 1 11 | = 106
330K
10r² + 3r + 0 = 0
e^{i\pi} + 1 = 0
det| 7 4 ; 4 8 | = 40
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det| 4 1 ; 1 5 | = 19
E = mc²
N₂ + 3H₂ ⇌ 2NH₃
det| 3 9 ; 0 4 | = 12
e^{i\pi} + 1 = 0