Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:20Z
∑_{k=1}^{n} k = n(n+1)/2
8β² + 2β + 0 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
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∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
390K
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 12 1 ; 1 13 | = 155
det| 7 4 ; 4 8 | = 40
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N₂ + 3H₂ ⇌ 2NH₃
det| 7 2 ; 3 8 | = 50
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det| 5 5 ; 2 6 | = 20
e^{i\pi} + 1 = 0