Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 05:07Z
det| 3 3 ; 5 4 | = -3
det| 7 6 ; 1 8 | = 50
479K
∇²β = 0
det| 7 4 ; 4 8 | = 40
129K
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
191K
E = mc²
CH₄ + 2O₂ → CO₂ + 2H₂O
1K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∑_{k=1}^{n} k = n(n+1)/2
473K
det| 3 7 ; 2 4 | = -2
det| 3 7 ; 2 4 | = -2
188K
∂t/∂β = 2t