Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 22:08Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
12β² + 9β + 3 = 0
det| 7 6 ; 1 8 | = 50
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∂z/∂n = 8z
e^{i\pi} + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
∑_{k=1}^{n} k = n(n+1)/2
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∫₀^∞ e^(-ψ²) dψ = √π / 2
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