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Math Dump /sym/7fd97a

id=1 · host=jp.commstar.world · 2026-10-19 04:42Z

E = mc²
ops_7798.tex
∂φ/∂t = 4φ
326K
spec_4768.mol
∑_{k=1}^{n} k = n(n+1)/2
198K
det| 10 7 ; 4 11 | = 82
spec_5771.mol
∑_{k=1}^{n} k = n(n+1)/2
155K
ops_8597.dat
∇²ω = 0
63K
λ = h/p
mat_6103.dat
N₂ + 3H₂ ⇌ 2NH₃
366K
ops_2907.tex
4γ² + 1γ + 7 = 0
201K
4θ² + 9θ + 6 = 0
eq_1210.eqn
det| 3 6 ; 0 4 | = 12
176K
spec_5703.json
∑_{k=1}^{n} k = n(n+1)/2
319K
det| 8 5 ; 5 9 | = 47
ops_6502.csv
∇ × E = −∂B/∂t
359K
spec_6630.dat
det| 7 4 ; 4 8 | = 40
263K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
d/dx [x^12] = 12x^11
3n² + 5n + 4 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
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