Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 05:00Z
∑_{k=1}^{n} k = n(n+1)/2
11y² + 4y + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
155K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
63K
d/dy [y^6] = 6y^5
8ω² + 6ω + 2 = 0
det| 9 4 ; 1 10 | = 86
319K
\frac{4}{2} \sum_{i=1}^{n} i^{2}