Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 20:44Z
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
234K
det| 3 7 ; 2 4 | = -2
278K
12φ² + 9φ + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
233K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
∑_{k=1}^{n} k = n(n+1)/2
100K
det| 7 4 ; 4 8 | = 40
330K
4z² + 8z + 0 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
139K
\frac{10}{5} \sum_{i=1}^{n} i^{2}
9ψ² + 7ψ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
λ = h/p
\lim_{β\to 0} \frac{\sin β}{β} = 1