Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:22Z
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
75K
8β² + 2β + 0 = 0
∫₀^∞ e^(-t²) dt = √π / 2
276K
∑_{k=1}^{n} k = n(n+1)/2
det| 7 6 ; 1 8 | = 50
191K
det| 9 4 ; 1 10 | = 86
390K
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 5 2 ; 3 6 | = 24
153K
det| 12 1 ; 1 13 | = 155
\lim_{t\to 0} \frac{\sin t}{t} = 1
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-θ²) dθ = √π / 2
det| 5 5 ; 2 6 | = 20