Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 00:15Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
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∑_{k=1}^{n} k = n(n+1)/2
479K
7x² + 6x + 1 = 0
det| 11 9 ; 0 12 | = 132
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
CH₄ + 2O₂ → CO₂ + 2H₂O
390K
5β² + 9β + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
338K