Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:03Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
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3β² + 6β + 2 = 0
F = ma
Fe₂O₃ + 3CO → 2Fe + 3CO₂
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\frac{8}{7} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
153K
1x² + 5x + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
473K
det| 3 6 ; 0 4 | = 12
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