Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:17Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-n²) dn = √π / 2
75K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
479K
3β² + 6β + 2 = 0
∫₀^∞ e^(-x²) dx = √π / 2
276K
det| 10 2 ; 1 11 | = 108
129K
F = ma
det| 7 9 ; 1 8 | = 47
191K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-φ²) dφ = √π / 2
1K
det| 9 4 ; 1 10 | = 86
153K
1x² + 5x + 7 = 0
∇²ψ = 0
det| 5 9 ; 0 6 | = 30
188K
det| 7 2 ; 3 8 | = 50
416K
3φ² + 8φ + 6 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}