Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:01Z
∑_{k=1}^{n} k = n(n+1)/2
det| 10 2 ; 1 11 | = 108
75K
8β² + 2β + 0 = 0
det| 7 2 ; 7 8 | = 42
129K
∑_{k=1}^{n} k = n(n+1)/2
det| 5 2 ; 3 6 | = 24
390K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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det| 5 3 ; 2 6 | = 24
473K