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Math Dump /sym/7fd97a

id=1 · host=jp.commstar.world · 2026-10-19 00:09Z

12r² + 5r + 0 = 0

det| 5 6 ; 6 6 | = -6

326K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

198K

iħ ∂ψ/∂t = Ĥψ

10β² + 4β + 1 = 0

155K

∇ × E = −∂B/∂t

63K

11x² + 6x + 2 = 0

ΔS ≥ 0

366K

∑_{k=1}^{n} k = n(n+1)/2

201K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

∇²θ = 0

176K

\lim_{z\to 0} \frac{\sin z}{z} = 1

319K

∑_{k=1}^{n} k = n(n+1)/2

359K

CH₄ + 2O₂ → CO₂ + 2H₂O

263K

\lim_{φ\to 0} \frac{\sin φ}{φ} = 1

233K

∇²n = 0

412K

det| 3 3 ; 0 4 | = 12

190K

det| 12 7 ; 5 13 | = 121

461K

\oint_C \vec{F}\cdot d\vec{r} = 0

246K

ΔS ≥ 0

439K

CaCO₃ → CaO + CO₂

91K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

314K

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