Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:24Z
11t² + 7t + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
198K
E = mc²
det| 7 4 ; 4 8 | = 40
63K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
CH₄ + 2O₂ → CO₂ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
359K
det| 5 6 ; 2 6 | = 18
263K