Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:25Z
11t² + 7t + 4 = 0
\frac{2}{2} \sum_{i=1}^{n} i^{2}
326K
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 10 2 ; 1 11 | = 108
366K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 11 4 ; 5 12 | = 112
176K
det| 9 4 ; 1 10 | = 86
319K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∑_{k=1}^{n} k = n(n+1)/2
233K