Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:40Z
∇²α = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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6φ² + 8φ + 4 = 0
∂φ/∂φ = 1φ
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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∫₀^∞ e^(-x²) dx = √π / 2
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det| 4 8 ; 1 5 | = 12
∑_{k=1}^{n} k = n(n+1)/2
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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 9 4 ; 1 10 | = 86
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det| 3 3 ; 4 4 | = 0
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