Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:21Z
11t² + 7t + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
198K
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 4 8 ; 3 5 | = -4
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
∫₀^∞ e^(-x²) dx = √π / 2
319K
det| 7 4 ; 4 8 | = 40
233K