Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 08:02Z
10t² + 7t + 4 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
326K
∑_{k=1}^{n} k = n(n+1)/2
198K
d/dα [α^9] = 9α^8
∑_{k=1}^{n} k = n(n+1)/2
155K
det| 8 7 ; 2 9 | = 58
det| 9 4 ; 1 10 | = 86
366K
∂β/∂n = 6β
∫₀^∞ e^(-φ²) dφ = √π / 2
176K
CH₄ + 2O₂ → CO₂ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
359K
8r² + 7r + 1 = 0
e^{i\pi} + 1 = 0
CaCO₃ → CaO + CO₂
ΔS ≥ 0