Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:40Z
∑_{k=1}^{n} k = n(n+1)/2
det| 4 8 ; 3 5 | = -4
479K
8β² + 2β + 0 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
276K
∑_{k=1}^{n} k = n(n+1)/2
det| 7 4 ; 4 8 | = 40
191K
\lim_{r\to 0} \frac{\sin r}{r} = 1
CH₄ + 2O₂ → CO₂ + 2H₂O
1K
det| 12 1 ; 1 13 | = 155
det| 11 4 ; 5 12 | = 112
473K
det| 3 1 ; 7 4 | = 5
338K
N₂ + 3H₂ ⇌ 2NH₃
Fe₂O₃ + 3CO → 2Fe + 3CO₂
188K
∫₀^∞ e^(-θ²) dθ = √π / 2