Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:47Z
2ψ² + 5ψ + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
75K
N₂ + 3H₂ ⇌ 2NH₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
129K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∇²z = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
1K
N₂ + 3H₂ ⇌ 2NH₃
8t² + 2t + 3 = 0
det| 7 4 ; 4 8 | = 40
188K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
416K
F = ma