Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:35Z
11t² + 7t + 4 = 0
det| 4 4 ; 5 5 | = 0
326K
E = mc²
det| 7 4 ; 4 8 | = 40
63K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 5 6 ; 7 6 | = -12
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
∫₀^∞ e^(-φ²) dφ = √π / 2
176K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 11 9 ; 0 12 | = 132
359K
det| 10 1 ; 4 11 | = 106
∑_{k=1}^{n} k = n(n+1)/2
233K
∑_{k=1}^{n} k = n(n+1)/2