Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:35Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
det| 1 1 ; 5 2 | = -3
276K
det| 11 9 ; 5 12 | = 87
129K
F = ma
CH₄ + 2O₂ → CO₂ + 2H₂O
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-φ²) dφ = √π / 2
1K
CH₄ + 2O₂ → CO₂ + 2H₂O
473K