Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:34Z
11t² + 7t + 4 = 0
det| 4 4 ; 5 5 | = 0
326K
E = mc²
CH₄ + 2O₂ → CO₂ + 2H₂O
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det| 11 9 ; 0 12 | = 132
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
CH₄ + 2O₂ → CO₂ + 2H₂O
∫₀^∞ e^(-t²) dt = √π / 2
359K
CH₄ + 2O₂ → CO₂ + 2H₂O
263K