Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 04:35Z
E = mc²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
326K
det| 10 7 ; 4 11 | = 82
det| 5 6 ; 2 6 | = 18
155K
∫₀^∞ e^(-n²) dn = √π / 2
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λ = h/p
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
366K
det| 7 4 ; 4 8 | = 40
201K
4θ² + 9θ + 6 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
176K
det| 8 5 ; 5 9 | = 47
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\oint_C \vec{F}\cdot d\vec{r} = 0
233K
d/dx [x^12] = 12x^11
3n² + 5n + 4 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0