Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 21:48Z
d/dx [x^11] = 11x^10
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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4r² + 1r + 1 = 0
∂φ/∂θ = 6φ
det| 5 3 ; 2 6 | = 24
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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det| 2 1 ; 7 3 | = -1
\frac{10}{1} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O