Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:11Z
∇ × E = −∂B/∂t
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\frac{8}{9} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
276K
F = ma
\oint_C \vec{F}\cdot d\vec{r} = 0
390K
10n² + 4n + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-γ²) dγ = √π / 2
det| 5 9 ; 0 6 | = 30
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det| 6 9 ; 4 7 | = 6