Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:13Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
det| 7 4 ; 4 8 | = 40
129K
F = ma
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
191K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
1K
∫₀^∞ e^(-t²) dt = √π / 2
188K