Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 18:09Z
11γ² + 9γ + 0 = 0
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
392K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
233K
5θ² + 1θ + 3 = 0
det| 7 4 ; 4 8 | = 40
100K
∑_{k=1}^{n} k = n(n+1)/2
∇ × E = −∂B/∂t
\lim_{α\to 0} \frac{\sin α}{α} = 1
\binom{n}{k} = \frac{n!}{k!(n-k)!}
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
iħ ∂ψ/∂t = Ĥψ