Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 21:42Z
d/dx [x^11] = 11x^10
∑_{k=1}^{n} k = n(n+1)/2
278K
4r² + 1r + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
392K
det| 10 9 ; 0 11 | = 110
233K
∂φ/∂θ = 6φ
∑_{k=1}^{n} k = n(n+1)/2
100K
det| 2 1 ; 7 3 | = -1
\frac{10}{1} \sum_{i=1}^{n} i^{2}
det| 9 4 ; 1 10 | = 86
412K
det| 4 4 ; 5 5 | = 0
223K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O