Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 04:32Z
E = mc²
det| 10 7 ; 4 11 | = 82
λ = h/p
\binom{n}{k} = \frac{n!}{k!(n-k)!}
366K
det| 9 4 ; 1 10 | = 86
201K
4θ² + 9θ + 6 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
319K
det| 8 5 ; 5 9 | = 47
\frac{1}{9} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O