Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:20Z
11t² + 7t + 4 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
198K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
155K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
63K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 5 3 ; 2 6 | = 24
366K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 4 8 ; 3 5 | = -4
176K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
263K
d/dy [y^11] = 11y^10
233K
det| 7 4 ; 4 8 | = 40
412K