Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 07:44Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
326K
7r² + 8r + 6 = 0
det| 3 6 ; 0 4 | = 12
155K
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
201K
det| 10 9 ; 3 11 | = 83
∑_{k=1}^{n} k = n(n+1)/2
319K
2ψ² + 6ψ + 0 = 0
det| 7 4 ; 4 8 | = 40
359K
ω = 2πf
∂ψ/∂t = 3ψ
6θ² + 3θ + 6 = 0