Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:52Z
2ψ² + 5ψ + 4 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
479K
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
276K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
CH₄ + 2O₂ → CO₂ + 2H₂O
191K
∇²z = 0
N₂ + 3H₂ ⇌ 2NH₃
8t² + 2t + 3 = 0