Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 16:57Z
7φ² + 4φ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
326K
det| 7 4 ; 4 8 | = 40
198K
E = mc²
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
366K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∫₀^∞ e^(-x²) dx = √π / 2
319K
d/dβ [β^2] = 2β^1
∑_{k=1}^{n} k = n(n+1)/2
359K
CaCO₃ → CaO + CO₂
det| 9 1 ; 5 10 | = 85