Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 23:52Z
d/dα [α^11] = 11α^10
\frac{3}{5} \sum_{i=1}^{n} i^{2}
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
100K
det| 7 4 ; 4 8 | = 40
330K
10r² + 3r + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
139K
e^{i\pi} + 1 = 0