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Math Dump /sym/7fd97a

id=1 · host=jp.commstar.world · 2026-10-19 07:46Z

ω = 2πf
eq_9374.mol
e^{i\pi} + 1 = 0
326K
spec_4768.mol
∑_{k=1}^{n} k = n(n+1)/2
198K
7r² + 8r + 6 = 0
eq_9015.json
\oint_C \vec{F}\cdot d\vec{r} = 0
155K
mat_6103.dat
N₂ + 3H₂ ⇌ 2NH₃
63K
∑_{k=1}^{n} k = n(n+1)/2
eq_8947.log
\oint_C \vec{F}\cdot d\vec{r} = 0
366K
spec_6630.dat
det| 7 4 ; 4 8 | = 40
201K
det| 10 9 ; 3 11 | = 83
eq_8998.eqn
\oint_C \vec{F}\cdot d\vec{r} = 0
176K
ops_1662.log
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
319K
2ψ² + 6ψ + 0 = 0
det| 2 5 ; 6 3 | = -24
ω = 2πf
∂ψ/∂t = 3ψ
6θ² + 3θ + 6 = 0
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