Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:09Z
11t² + 7t + 4 = 0
det| 9 4 ; 1 10 | = 86
326K
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
366K
CH₄ + 2O₂ → CO₂ + 2H₂O
\frac{2}{2} \sum_{i=1}^{n} i^{2}
176K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
ΔS ≥ 0