Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:23Z
11t² + 7t + 4 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
198K
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
366K
\lim_{t\to 0} \frac{\sin t}{t} = 1
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 5 6 ; 7 6 | = -12
176K
\lim_{t\to 0} \frac{\sin t}{t} = 1
319K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∫₀^∞ e^(-φ²) dφ = √π / 2
359K