Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:10Z
11t² + 7t + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
198K
E = mc²
CH₄ + 2O₂ → CO₂ + 2H₂O
63K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
366K
det| 9 4 ; 1 10 | = 86
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
176K
∑_{k=1}^{n} k = n(n+1)/2
319K
det| 5 2 ; 3 6 | = 24
359K